Question

2) if 2 numbers
are
in the
ratio 3:7.
if 5 Subtracted from
the number
the ratio
becomes 4:11.
find out the numbers.?​

Answer 1

Answer:

Let, the two numbers be 3x and 7x.

(3x - 5)/(7x - 5) = 4/11 ( cross multiplication)

=> 11(3x - 5) = 4(7x - 5)

=> 33x - 55 = 28x - 20

=> 33x - 28x = -20 + 55

=> 5x = 35

=> x = 35/5

=> x = 7

so, the numbers are 21 and 49.

ì höpê ït wíll hēlp yõú.˘⌣˘.

Answer 2

Let the two numbers be 3x and 7x.

Subtract 5 from each of these numbers. We get 3x-5 and 7x-5. From the given problem, the ratio of these new numbers is 4:11. Then,

(3x−5) / (7x−5) = 4/11

Cross-multiply

(3x−5)×11 =(7x−5)×4

Multiplying 11 inside 3x-5 and 4 inside 7x-5,

33x−55 = 28x−20

33x−28x = −20+55

5x = 35

x = 7

The required numbers are 3x = 3×7 = 21 and 7x = 7×7 = 49.

I hope you satisfied with my answer.

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