Question

2. If (2 sin x + 3 cos x) = 2, prove that (3sin x - 2 cos x) = +3.​

Answer 1

Answer:

Given →2sin x+3cos x=2

→2sin x=2−3cos x

→(2sinx)²=(2−3cosx)²

→4sin²x=4−6cosx+9cos²x

→4−4cos²x=4−6cosx+9cos²x

→13cos²x−6cosx=0

→cos x(13cos x−6)=0

→cos x=0,6/13

→x=90°

Now,

,

3sin x−2cos x=3sin 90 °−2cos90°=3

hope it's helpful❤✨