Question

2. If 3 cot A = 4 cos A, then the relation between sec A and tan A is (a) 4 sec A=3 tan A (b) 3 sec? A - 4 tan? A=0 (c) 4 sec2 A-3 tan? A=0 (d) 3 sec A-4 tan A=0 2​

Answer 1

Answer:

Step-by-step explanation:

3 cot A = 4 cos A

3 = cos A

4      cot A

3 = cos A ÷ cot A

4

3 =   1      ÷    1    

4     sec A    tan A

3 =     1     x tan A

4     sec A

3 = tan A

4     sec A

3 sec A = 4 tan A

3 sec A - 4 tan A = 0

Answer 2

Step-by-step explanation:

here is your answer

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