Question

2. If a = 0,b= -1, find the value of (a) a3 + +b3+3a2b+3ab2​

Answer 1

Answer:

a3−b3=(a−b)3+3ab(a−b)=(a−b)(a2+b2+ab)

Step-by-step explanation:

First method

a3+b3=a3+ab2−a2b+b3+a2b−ab2=a(a2+b2−ab)+b(a2+b2−ab)=(a+b)(a2+b2−ab)

To find a3−b3 , replace b with − b

a3−b3=(a−b)(a2+b2+ab)

Second method

(a+b)3=(a+b)2(a+b)=(a2+2ab+b2)(a+b)=a3+3a2b+3ab2+b3=a3+b3+3ab(a+b)

a3+b3=(a+b)3−3ab(a+b)=(a+b)(a2+b2−ab)

For a3−b3 , replace b with −b

a3−b3=(a−b)3+3ab(a−b)=(a−b)(a2+b2+ab)

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Answer 2

Answer:

your answer is -1 correct or not