Question

2. If a = 41 +3j and 5 = 31 +4j. the magnitude of a - b is

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Answer 1

Correct question:-

If a = 4i +3j and b = 3i +4j. the magnitude of |a - b| is

Answer:-

Given:-

a=4i +3j and b=3i +4j.

so,

Finding first a -b value

a -b = (4 i+3j)-(3i+4j)

a-b= (4-3)i + (3-4)j

a - b= 1i - 1j

Now magnitude of a - b

|a - b|= [(x-component)^2 + ( y-component)^2] ^1/2

$\sqrt{} {1}^{2} + {1}^{2}$

|a-b|=

$\sqrt{2}$

|a-b|= 1.414.

So, magnitude of |a-b|is 1.414.

Answer 2

Answer: √2

Explanation:

Given,

a = 4i + 3j

And,

b = 3i + 4j

a - b = (4i + 3j) - (3i + 4j)

a - b = 4i + 3j - 3j - 4j

a - b = (4-3)i + (3 - 4)j

a - b = (1)i + (-1)j

a - b = i - j

Taking modulus of both sides,

|a - b| = √(1² + 1²)

|a - b|  = √(1+1)

|a - b| = √2

Note:- Modulus of a vector ai + bj +ck is

given by √(a²+b²+c²)