Computer Science, asked by syamalabodduru15, 5 hours ago

2. If a 7-bit sliding window size is used, how many packets can be sent before the transmitter has to stop and wait for an acknowledgment? A 3-bit field is used to hold the window size of the sliding window protocol. Number of possible sequence numbers that can be generated equals 8 but a sender can have only at most 7 unacknowledged or outstanding​

Answers

Answered by arjunf724
5

Answer:

blah blah blah blah blah

Answered by Khanreema
0

Answer:

As 7 bits are used for sequence number so total sequence numbers will be 2^{7} = 128. So maximum window size should be 128.

Explanation:

However, window size is also affected by Transmission Time (Tt) and Propagation Time (Tp). Essentially, we are transmitting data via a physical medium. And the maximum window size for this medium will be 1+2(Tp/Tt).

So, in order to meet both constraints and prevent congestion, the window size will be the smallest of these two, i.e. min(27, 1+2(Tp/Tt)).

#SPJ2

Similar questions