Math, asked by vishal25505, 9 months ago


2. If a and B are zeroes of the quadratic polynomial x²+ x-2, find the value of ¹/a and ¹/b

Answers

Answered by TħeRøмαи
3

f(x)= x² + x - 2 =0

using substitution method

x²+ 2x- x - 2 =0

x(x+2)-1(x+2)=0

x= -2

and x= 1

take α = -2 and β = 1

Now,

1/-2 - 1/1

-3/2

Answered by ayushyadav143
1

Hey there,

"If alpha and beta are the zeroes of the polynomial"

Taking this into account

1/alpha - 1/beta = 1/0 - 1/0

= infinity - infinity

which is not defined

if incase

"If alpha and beta are the solutions of the polynomial"

x^2 + x - 2 =0

(x+2)(x -1) = 0

=> x= -2 or x =1

therefore (alpha,beta) = (1,-2) or (-2,1)

1/alpha - 1/beta

= (3/2) or -(3/2)

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