Math, asked by nantumodak999, 8 months ago

2.
If a - b = 6 and a^2= 42, find the value of a b​

Answers

Answered by LimaRachel20
2

Answer:

0.49

Step-by-step explanation:

a^2 =42

a= root of 42

then ,a =6.480.......

................. .............................

~a-b =6 ~

~6.48 - b = 6 ~

~ b = 6.48 - 6 ~

~ b = 0.48 ~

Answered by vinuevarghese
0

Answer:

Step-by-step explanation:

If a-b=6 and a^2+b^2=42 find the value of ab

To find ab

(a-b)^{2} = a^{2} + b^{2}-2ab

6^{2}=42-2ab

36=42-2ab

42-36-2ab = 0

6-2ab=0

6=2ab

Therefore ab = 6/2 = 3

Similar questions