Question

2. If a + b + c = 0, then what is the value of a^3+ b^3 + c^?
​

Answer 1

Answer:

$by \: using \: identity : \\ {a}^{3} + {b}^{3} + {c}^{3} - 3abc \\ = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca) \\ < a + b + c = 0 > put \: it \\ {a}^{3} + {b}^{3} + {c}^{3} - 3abc = 0 \\ \: {a}^{3} + {b}^{3} + {c}^{3} = 3abc$