Question

2 if A-BC and I EAC) = 11 e LBC) = 65
then complete the activity to find
ICAC) - 11; ICBC = 6.5
LILABIT = 1 CAC​

Answer 1

Step-by-step explanation:

As the unit digit of the product is 5 therefore the unit digit of one of

the numbers is 5 and the unit digit of the other number is odd

Therefore AB5 x 5BA = 65125 where A = 1, 3, 5, 7 or 9

As the product

of two three-digit number is a five-digit number and not a six-digit

number A can only be equal to 1. IB5 x 5B1 = 65125

The digit sums of

both numbers 1B5 and 5B1 will be same Therefore the product would give

digit sum of a perfect square The digit sum on the R. H. S. is 1

Therefore the digit sum of each number can be 1 or 8 Correspondingly B

will be 4 or 2 (as digit sum cannot be equal to 1)

Keeping B = 2 we can see that 125 x 521 = 65125

Answered 

Answer 2

Answer:

l don't know the answer

sorry