Question

2)If a bullet of mass 40 gm is fired from a
gun of mass 8 kg with a velocity of
800m/sec, the recoil velocity of gun is:​

Answer 1

Answer:

Recoil velocity of gun is -4 m/s .

Given that mass of bullet (m') = 40 gm = (40/1000) = 0.04 kg. Mass of gun (m") = 8 kg. Velocity of bullet after firing (v') = 800 m/s.

Explanation:

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Answer 2

Answer:

M1=40g=0.04kg

M2=8kg

V1=800m/s

V2 =?

according to laws of conservation of momentum

M1v1=M2v2

0.04*800=8*V2

V2 =0.04*800/8

V2=0.04*100=4

V2=4m/s

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