Question

2. If A =[k 3 10 5]

is a singular matrix, then the value of k is equal to :


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Answer 1

Step-by-step explanation:

Given that:2×2 matrix

$A=\left[\begin{array}{cc}k&10\\3&5\end {array}\right]$

To find:

Value of k for which the given matrix A is singular

Solution:

A square matrix is said to be singular,if determinant of matrix is zero.

So,Find the value of determinant and equate it to zero.

$|A| = 0$

$\left|\begin{array}{cc}k&10\\3&5\end {array}\right|=0$

$5k - 30 = 0 \\ \\ 5k = 30 \\ \\ k = \frac{30}{5} \\ \\ k = 6$

The value of k should be 6,for the matrix A to be singular.

Hence option B is correct; k =6

Hope it helps you.

Answer 2

Answer:

The value of k should be 6,for the matrix A to be singular.

The value of k should be 6,for the matrix A to be singular.Hence option B is correct; k =6