Math, asked by poonamkrishankumar7, 19 days ago

2. If a man goes 24 m towards East and then 10 m towards North. How far he is starting from? (a) 26 m (b) 17 m (c) 18 m (d) None of these​

Answers

Answered by sukantkumartripathy8
25

Answer:

option a

Step-by-step explanation:

this is the explanation

Attachments:
Answered by tennetiraj86
24

Answer:

(a) 26 m

Step-by-step explanation:

Given :-

A man goes 24 m towards East and then 10 m towards North.

To find :-

How far he is starting from?

Solution:-

Given that

A man goes 24 m towards East and then 10 m towards North.

The man goes first towards to the East for 24 m

And then he moved towards the North for 10 m

If we convert this data then we get a right angled triangle.

Let the traingle XYZ

XY = 10 m

YZ = 24 m

Initial point = Z

End point = X

Distance between Z and X = XZ

We know that

By Pythagoras Theorem,

XZ² = XY² + YZ²

=> XZ² = (10)²+(24)²

=> XZ² = 100+576

=> XZ² = 676

=> XZ = ±√676

=> XZ = ±26

Distance can't be negative.

=> XZ = 26 m

Therefore , XZ = 26 m

Answer:-

The man is 26 m far from the starting point.

Used Theorem:-

Pythagoras Theorem:-

" In a right angled triangle, The square of the hypotenuse is equal to the sum of the squares of the other two sides".

Attachments:
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