2. If a square and a rhombus stand on the same base, then find the ratio of the areas of the
and the rhombus.
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Consider a square and rhombus standing on the same base 'a'. All the sides of a square are of equal length. Similarly all the sides of a rhombus are also of equal length. Since both the square and rhombus stands on the same base 'a',
Length of each side of the square = a
Length of each side of the rhombus = a
Area of the sqaure = a2 ...(1)
From the diagram, sin θ = ha
=> h = a sin θ
Area of the rhombus = ah = a × a sin θ = a2 sin θ ...(2)
From (1) and (2)
Area of the squareArea of the rhombus=a2a2sinθ=1sinθ
Since 0° < θ < 90°, 0 < sin θ < 1. Therefore, area of the square is greater than that of rhombus, provided both stands on same base.
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