Question

2. If a the initial velocity of a body is 2m/s and it acquires a final velocity
of 8m/s with an acceleration of 10m/square
. Find the distance travelled by
the body
​

Answer 1

Answer:

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Explanation:

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Answer 2

• initial velocity=u=2m/s
• Final velocity=v=8m/s
• Acceeleration=a=10m/s^2
• Distance=s

First we need to find time(t)

$\boxed{\sf a=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto t=\dfrac{v-u}{a}$

$\\ \sf\longmapsto t=\dfrac{8-2}{10}$

$\\ \sf\longmapsto t=\dfrac{6}{10}$

$\\ \sf\longmapsto t=0.6s$

Now using 2nd equation of kinematics

$\boxed{\sf s=ut+\dfrac{1}{2}at^2}$

$\\ \sf\longmapsto s=2(0.6)+\dfrac{1}{2}\times 10(0.6)^2$

$\\ \sf\longmapsto s=1.2+5(0.36)$

$\\ \sf\longmapsto s=1.2+1.8$

$\\ \sf\longmapsto s=3m$