2. If a1/3 + b2/3 + c = 0 then show that (a + b + c3)3 = 27ab2c3
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Answer:
Step-by-step explanation:
a
1/3
+b
1/3
+c
1/3
=0
(a
1/3
)
3
+(b
1/3
)
3
+(c
1/3
)
3
=3a
1/3
b
1/3
c
1/3
⇒a+b+c=3(abc)
1/3
⇒(a+b+c)
3
=27abc
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