Question

-2) If cas= -3 & 180° L6 2 270° than value
of tand + seco is​

Answer 1

Answer:

-1/3

Step-by-step explanation:

theta is in third quadrant

sin^2x = 1- cos^2x

sin^2x = 1- 9/25 = 16/25

sinx = -4/5 because in third quadrant sin is negative

now tanx + secx = (sinx+1)/cosx

(-4/5+1)/-3/5

(1/5)/-3/5

-1/3

hope it helps u

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