Biology, asked by rayosharvy4, 5 months ago

2. If each flip represents 5730 years, how many years would have taken for at
of your Carbon-145-centavo coins to become Nitrogen-145-centovo con​

Answers

Answered by babli71kafeel
4

Answer:

it will take 5370 years

Answered by shilpa85475
0

If each flip represents 5730 years, how many years would have taken for at .

  • If each flip represents 5730 years, how many years would it have taken for all of your Carbon-14 to decay?  
  • It took 11 flips for all of my 100 atoms of Carbon-14 to decay.  
  • If I multiply 11 times 5,730, it would take 63,030 years for my 100 atoms of Carbon-14 to decay.
  • Nitrogen-14 decay 100 5 4 3 2 1 6 0 80 70 60 50 40 30 20 10 0.
  • Percentage parent isotope remaining Half-life.
  • If it is in  half-life of carbon-14 is 5730 years.
  • Therefore, after 1 half-life there is 50%=1/2 of the original amount left. Half-lives there is 25%=1/4 of the original amount left.
  • Half-lives there is 12.5%=1/8 of the original amount left.
  • 1-7/8=1/8 So, your answer would be the time it takes for carbon-14 to elapse 3 half-lives. 5730*3=17190.
Similar questions