Question

2. If J=(2 2 -1 6), K=(4 -1 0 5) and L=(x y -1 z) and J–K=L, find the values x,yandz​

Answer 1

Answer:

ans: x= -2 y=13 z= -21

Step-by-step explanation:

here if we represent in vector form of J=2i+2j-16k , K=4i-10j+5k and L=xi+(y-1)j+zk

here given J-K=L so on solving

(2i+2k-16k)-(4i-10j+5k)=(xi+(y-1)j+zk)

so here

(-2i+12j-21k)=[xi(y-1)j+zk]. on comparing

we get

X= -2 Y=12 Z=-21

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