Question

2] If l = 400 mA and Ic = 1.2 mA then ß is
i) 30 ii) 3 iii) 0.3 iv) 0.06​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The value of β is equal to 0.003. i.e.none of the options is correct.

Explanation:

The current gain for a common emitter transistor configuration is given as,

$\beta=\frac{I_c}{I_b}$        (1)

Where,

β=current gain in common emitter configuration

$I_c$=current through the collector region of the transistor

$I_b$=current through the base region of the transistor

From the question we have,

The net current through the transistor(I)=400mA

The current through the collector region of the transistor($I_c$)=1.2mA

So,

$I=I_c+I_b$          (2)

By substituting the required values in equation (2) we get;

$400mA=1.2mA+I_b$

$I_b=400mA-1.2mA=398.8mA$     (3)

By substituting the required values in equation (1) we get;

$\beta=\frac{1.2mA}{398.8mA}=0.003$    (4)

Hence, the current gain β is equal to 0.003.i.e.none of the options is correct.