Question

2) If length of rectangle is 24 cm and its breadth is 10 cm. find the diagonal.​

Answer 1

Answer:-

$\blue{\bigstar}$ Length of the Diagonal $\large\leadsto\boxed{\tt\pink{26 \: cm}}$

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• Given:-

• Length of rectangle = 24 cm

• Breadth of rectangle = 10 cm

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• To Find:-

• The length of the diagonal

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✯ Figure:-

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(2,3.5){\sf\large 24 cm}\put(-1.4,1.4){\sf\large 10 cm}\qbezier(5,3)(5,3)(0,0)\put(2.5,1.8){\bf d}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

• SOLUTION:-

We know,

$\pink{\bigstar}$ $\underline{\boxed{\bf\green{Diagonal = \sqrt{(length)^2 + (breadth)^2}}}}$

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• Substituting in the Formula:-

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➪ $\sf Diagonal = \sqrt{(24)^2 + (10)^2}$

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➪ $\sf Diagonal = \sqrt{576 + 100}$

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➪ $\sf Diagonal = \sqrt{676}$

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★ $\large{\bf\red{26 \: cm}}$

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Therefore, the length of the diagonal is 26 cm.