Question

2) If length of rectangle is 24 cm and its breadth is 10 cm. find the diagonal.​

Answer 1

• Given

• Length of a rectangle = 24 cm
• Breadth of a rectangle = 10 cm

• To find

• Its diagonal

• Solution

Formula to find diagonal of rectangle -

$\red{\bigstar}$ $\large { \boxed{ \sf {\green{diagonal \: = \sqrt{ {w}^{2} + {l}^{2} } }}}}$

Substitute the given values.

$: \implies \sf{ \sqrt{ {24}^{2} + {10}^{2} } }$

$: \implies \sf{ \sqrt{ 576 + 100 } }$

$: \implies \sf{ \sqrt{26 \times 26} }$

$: \implies \sf{26 \: cm}$

$\red{\bigstar}$ $\large { \boxed{ \sf {\green{diagonal \: = 26 \: cm}}}}$

$\blue{\bigstar}$ Diagram -

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(2,3.5){\sf\large 24 cm}\put(-1.4,1.4){\sf\large 10 cm}\qbezier(5,3)(5,3)(0,0)\put(2.5,1.8){\sf d}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\sf D}\put(5.3,-0.4){\sf B}\put(5.3,3.2){\sf C}\end{picture}$

Answer 2

Given :

• Length of the reactangle = 24 cm
• Breadth of the rectangle = 10 cm

To Find :

• The diagonal of rectangle = ?

Solution :

Let's find the diagonal of the rectangle by given below formula :

• Diagonal = √(Length)² + (Breadth)²

Now,just simply plug in the given values in above formula :

→ Diagonal = √(24)² + (10)²

→ Diagonal = √576 + 100

→ Diagonal = √676

→ Diagonal = 26 cm

• Hence,the diagonal of rectangle is 26 cm.

Properties of rectangle :

• The diagonal of rectangle bisect each other.
• The opposite side of rectangles are parallel.
• The opposite sides of rectangle are equal.
• A rectangle whose side lengths are x and y has perimeter 2x + 2y