Question

2. If lengths of the parallel sides of a trapezium are
7.
1
8
cm, 6 cm and height is 5 cm, find the area of
2.
the trapezium
8
10cm​

Answer 1

Correct Question :-

If length of a parallel sides of trapezium are 8.1/2 centimetre 6 cm and height is 5 cm find the area of trapezium.

To find :-

• Area of trapezium

Solution :-

• Length of parallel sides = 8 ½ and 6cm
• Height of trapezium = 5cm

According to the question

→ Area of trapezium = ½ × Sum of parallel sides × height

→ ½ × (a + b) × h

→ ½ × (8 ½ + 6) × 5

→½ × (17/2 + 6) × 5

→ ½ × (17 + 12/2) × 5

→ ½ × 29/2 × 5

→ 145/4

→ 36.25cm²

Hence,

• Area of trapezium is 36.25 cm²

Extra Information

• Area of rectangle = length × breadth
• Area of square = side × side
• Perimeter of square = 4 × side
• Perimeter of rectangle = 2(length + breadth)
• Area of rhombus = ½ × product of diagonals
• Area of Parallelogram = base × height

Answer 2

Correct Question :

If lengths of the parallel sides of a trapezium are 8½ cm, 6 cm and height is 5 cm, find the area of the trapezium

Solution :

Given ,

• The parrallel sides of trapezium are 8½ cm and 6 cm and its height is 5 cm

We know that , the area of trapezium is given by

$\boxed{ \sf{Area = \frac{1}{2} \times (Sum \: of \: parallel \: sides) \times (Height) }}$

Thus ,

$\sf \mapsto Area = \frac{1}{2} (8 \frac{1}{2} \times 6) \times 5 \\ \\ \sf \mapsto Area = \frac{1}{2} ( \frac{17}{2} + 6) \times 5 \\ \\ \sf \mapsto Area = \frac{1}{2} ( \frac{29}{2} \times 5) \\ \\ \sf \mapsto Area = \frac{145}{4} \\ \\ \sf \mapsto Area = 36.2 \: \: {cm}^{2}$

$\sf \therefore{ \underline{ {The \: area \: of \: trapezium \: is \: 36.2 \: {cm}^{2} }}}$