Chemistry, asked by hadiribu, 6 months ago

2. If M represents an atom of an 1 point
alkaline earth metal, the
correct formula for a
compound of this atom with
sulphur is:
M2S
O
MS2
0 MS3
OMS​

Answers

Answered by priti19188
0

Answer:

HI GUYS MARK ME BRAINLIEST.

Explanation:

(A) An oxygen atom is smaller as compared to sulphur; so in oxygen, there is more inter-electronic repulsion than that of sulphur.(B) Charge increases so size decrease and number of electrons per proton also decreases; so valence shell electron gradually becomes more tightly held by the nucleus. Hence ionization energies of an atom always increase.(C) Valance shell electron configuration of As is ns 2 np

(A) An oxygen atom is smaller as compared to sulphur; so in oxygen, there is more inter-electronic repulsion than that of sulphur.(B) Charge increases so size decrease and number of electrons per proton also decreases; so valence shell electron gradually becomes more tightly held by the nucleus. Hence ionization energies of an atom always increase.(C) Valance shell electron configuration of As is ns 2 np 3

(A) An oxygen atom is smaller as compared to sulphur; so in oxygen, there is more inter-electronic repulsion than that of sulphur.(B) Charge increases so size decrease and number of electrons per proton also decreases; so valence shell electron gradually becomes more tightly held by the nucleus. Hence ionization energies of an atom always increase.(C) Valance shell electron configuration of As is ns 2 np 3 (half filled stable configuration) and valence shell electron configuration of Se is ns

(A) An oxygen atom is smaller as compared to sulphur; so in oxygen, there is more inter-electronic repulsion than that of sulphur.(B) Charge increases so size decrease and number of electrons per proton also decreases; so valence shell electron gradually becomes more tightly held by the nucleus. Hence ionization energies of an atom always increase.(C) Valance shell electron configuration of As is ns 2 np 3 (half filled stable configuration) and valence shell electron configuration of Se is ns 2

(A) An oxygen atom is smaller as compared to sulphur; so in oxygen, there is more inter-electronic repulsion than that of sulphur.(B) Charge increases so size decrease and number of electrons per proton also decreases; so valence shell electron gradually becomes more tightly held by the nucleus. Hence ionization energies of an atom always increase.(C) Valance shell electron configuration of As is ns 2 np 3 (half filled stable configuration) and valence shell electron configuration of Se is ns 2 np

(A) An oxygen atom is smaller as compared to sulphur; so in oxygen, there is more inter-electronic repulsion than that of sulphur.(B) Charge increases so size decrease and number of electrons per proton also decreases; so valence shell electron gradually becomes more tightly held by the nucleus. Hence ionization energies of an atom always increase.(C) Valance shell electron configuration of As is ns 2 np 3 (half filled stable configuration) and valence shell electron configuration of Se is ns 2 np 4

(A) An oxygen atom is smaller as compared to sulphur; so in oxygen, there is more inter-electronic repulsion than that of sulphur.(B) Charge increases so size decrease and number of electrons per proton also decreases; so valence shell electron gradually becomes more tightly held by the nucleus. Hence ionization energies of an atom always increase.(C) Valance shell electron configuration of As is ns 2 np 3 (half filled stable configuration) and valence shell electron configuration of Se is ns 2 np 4 (

I HOPE IT'S HELP YOU .

Similar questions