Math, asked by shrawanikadam1980, 7 months ago

2) If n(A) = 20, n(B) = 28 and n(AUB) = 36 then n(ANB) = ?

Answers

Answered by Anonymous

7

Answer:

36 = 20+28-x

36=48-x

x = 48-36

x = 12...

hope this helps u mate

Answered by AkshayKatke

2

Answer:

below is your answer:

Step-by-step explanation:

n(AUB=n(A)+n(B)-n(AnB)

36 = 20+28-x

36=48-x

x = 48-36

x = 12...

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