2. If n(A) =45, n(A ∪ B)=70, and n(A∩ B)=25, then find n(B)?
Answers
Answer:
There is a mathematical relation between union and intersection of Two sets,
Let A and B be two sets, Then the formula will be,
n(AUB) = n(A)+ n(B) - n(AnB),
Given data, n(A) = 45,
n(B) = 52,
n(AUB) = 70,
n(AnB) = ?,
Substituting them in above Formula,
=> 70 = 45 + 52 - n(AnB),
=> 70 = 97 - n(AnB),
=> n(AnB) = 97-70,
=> n(AnB) = 27,
Therefore: The a answer is 27,
Answer:
n(AuB) = n(A) + n (B) -n(AnB) —————-1
n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18
n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18With these 2 we can calculate n(A)
- n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18With these 2 we can calculate n(A)n(A-B) = n(A) - n(AnB)
- n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18With these 2 we can calculate n(A)n(A-B) = n(A) - n(AnB)18 = n(A) - 25
- n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18With these 2 we can calculate n(A)n(A-B) = n(A) - n(AnB)18 = n(A) - 25=> n(A) = 18 + 25 = 43
n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18With these 2 we can calculate n(A)n(A-B) = n(A) - n(AnB)18 = n(A) - 25=> n(A) = 18 + 25 = 43now to calculate n(B) we can substitute all the values in equation 1
- n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18With these 2 we can calculate n(A)n(A-B) = n(A) - n(AnB)18 = n(A) - 25=> n(A) = 18 + 25 = 43now to calculate n(B) we can substitute all the values in equation 170 = 43+ n(B) - 25
- n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18With these 2 we can calculate n(A)n(A-B) = n(A) - n(AnB)18 = n(A) - 25=> n(A) = 18 + 25 = 43now to calculate n(B) we can substitute all the values in equation 170 = 43+ n(B) - 2570 = n(B) + 18
- n(AuB) = n(A) + n (B) -n(AnB) —————-1We have n(AnB) = 25 and n(A-B) = 18With these 2 we can calculate n(A)n(A-B) = n(A) - n(AnB)18 = n(A) - 25=> n(A) = 18 + 25 = 43now to calculate n(B) we can substitute all the values in equation 170 = 43+ n(B) - 2570 = n(B) + 18n(B) = 70–18 = 52