Question

2) If n(A×B) = 20 and( A) = 5 , then , then n(B )_____.

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Answer 1

Answer:

n(B) = 4

n(A×B)=20

n(5×B)=20

n(B)=4

Answer 2

Given: n(A×B) = 20

           (A) = 5

To find: n(B)

Solution:

• Let A be 'A'
• Let B be 'B'

• According to the question:

n(A×B) = 20 (where (A) = 5)

• By putting (A) = 5 in n(A×B) = 20, we get:

n(5×B) = 20

• For once, forget 'n':

(5×B) = 20

• Open the bracket:

5×B = 20

• Take 5 to other side and hence, transform the operation from multiply to divide.

B = $\frac{20}{5}$

• Divide now:

B = 4

Hence, the value of B is 4.