Question

-2. If n capacitors each having same capacitance Care
connected in series then equivalent capacitance
will be
a. nc
16. C/n
C. C
d. none

Answer 1

Answer:

Correct answer is Option (b) C/n.

Explanation:

Equivalent capacitance when capacitors are connected in series is ,

                          $\frac{1}{Ceq}=1/c_1+1/c_2+1/C_3$    and so on..

Here, $C_1 =C_2=C_3 ...=C_n=C$

⇒ $1/Ceq=1/C+1/C+1/C+....$

⇒$1/Ceq=n/C$

taking reciprocal,

⇒$Ceq = \frac{C}{n}$ = option (b)