Question

2 If one of the zeroes of the polynomial p(x) is (-2) then the value of k is (1 Point) p(x) = kx^2-kx+1 ​

Answer 1

Answer:

k = -1/6

Step-by-step explanation:

p(x) = kx^2 -kx +1

p(-2) = 0

p(-2) = k(-2)^2-k(-2) +1

p(-2) = 4k + 2k +1

0 = 6k +1

6k = -1

k = -1/6