Math, asked by opgamingyt, 9 months ago

2. If one of the zeroes of the quadratic polynomial (k – 1) x^2 – kx + 1 is – 3, then the value of k is

Answers

Answered by atahrv
2

Answer:

\green\large\boxed{\star\:\:\:k=\frac{2}{3}\:\:\:\star }

Step-by-step explanation:

Given:-

  -3 is a root of Quadratic Equation (k-1)x² - kx + 1.

To Find:-

   The Value of k .

Solution:-

  p(x)=(k-1)x² - kx + 1=0

Now, it is given that (-3) is a root of this Quadratic Equation.

∴ Putting x=3:-

⇒p(-3)=(k-1)(-3)² - k(-3) + 1=0

⇒(k-1)(9)+3k+1=0

⇒9k-9+3k+1=0

⇒12k=8

\implies k=\frac{8}{12}

\implies\boxed {k=\frac{2}{3}}

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