2) If one of zeros of the quadratic polynomial (R-1)x?+ 2kX+ 3
is 1
1 , then find value of k.
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2) If one of zeros of the quadratic polynomial (R-1)x?+ 2kX+ 3
is 1
1 , then find value of k.
Given that, one of the zeroes of the quadratic polynomial say p(x) = (k- 1)x2 + kx + 1 is -3,then p(-3) = 0
⇒ (k-1)(-3)2 + k(-3) + 1 = 0
⇒ 9(k-1)-3k + 1 = 0
⇒ 9k - 9 - 3k + 1 = 0
⇒ 6k - 8 = 0
∴ k = 4/3
Step-by-step explanation:
Hope that helps
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