Question

2. If one root of the equation 2x2 + ax + 6 = 0 is 2 then a = ?​

Answer 1

Answer:

2(2)²+a(2)+6 = 0

8+2a+6 = 0

2a+14 = 0

2a=-14

a = -14/2

a = - 7

Answer 2

Concept Introduction:

Using the equation x = (-b (b2 - 4ac))/2a, the roots are determined. D = b2 – 4ac serves as the discriminant. The equation contains two separate and actual roots if D > 0. The equation has two complex roots if D 0.

Given: The equation and $2$ is one of the root of this equation.

To Find:

We have to find the value of, 'a' in given equation.

Solution:

According to the problem,

Since $2$ is one of the root of this equation if we value of root in equation then it should come $0$.

⇒ $2x^{2} +ax+6=0$

⇒$2*2^{2} +a*2+6=0$

⇒$8+2a+6=0$

⇒$a=-14/2=-7$

Final Answer:

The value of a=$-7$.

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