Question

2.If one zero of the polynomial x^3+3x+k is 2 then the value of k is.
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Answer 1

The value of k is - 14 .

Answer 2

AnsWer :

k = - 14.

Given :

• One zeros of the polynamial x³ + 3x + k is 2.

To Find :

The value of K

Solution :

Let,

• P ( x ) = x³ + 3x + k
• One zeros be x = 2.

When,

• Putting the value of 2 as place of x polynomial P( x ) it becomes 0.
• P ( 2 ) = 0.

$\rule{90}2$

A/Q,

$\tt : \implies p(x) = {x}^{3} + 3x + k.$

$\tt : \implies p(2) = {x}^{3} + 3x + k.$

$\tt : \implies 0= {2}^{3} + 3 \big(2 \big)+ k.$

$\tt : \implies 0 = 8+ 6+ k.$

$\tt : \implies k = - 14.$

Therefore, the value of k is - 14.

Answer 3

AnsWer :

k = - 14.

Given :

• One zeros of the polynamial x³ + 3x + k is 2.

To Find :

The value of K

Solution :

Let,

• P ( x ) = x³ + 3x + k
• x = 2.

When,

• Putting the value of 2 as place of x polynomial P( x ) it becomes 0.
• P ( 2 ) = 0.

A/Q,

$\tt : \implies p(x) = {x}^{3} + 3x + k$

$\tt : \implies p(2) = {x}^{3} + 3x + k$

$\tt : \implies 0= {2}^{3} + 3 \big(2 \big)+ k$

$\tt : \implies 0 = 8+ 6+ k$

$\tt : \implies k = - 14$

Therefore, the value of k is - 14.