Question

2.
If p = 3, q = 2, r = 5, find the value of 2p²+ 3q-r² + 2pr - 5pqr​

Answer 1

Step-by-step explanation:

Given :- p=3 , q=2 , r =5

$2 {p}^{2} + 3q - {r}^{2} + 2pr - 5pqr \\ = 2 \times {3}^{2} + 3 \times 2 - {5}^{2} + 2 \times 3 \times 5 - 5 \times 3 \times 2 \times 5 \\ = 2 \times 9 + 6 - 25 + 30 - 150 \\ = 18 + 6 - 25 + 30 - 150 \\ = 54 - 175 = - 121$

Answer 2

Given

we have given p= 3 ,q= 2 & r= 5

To Find

We have to find the value of 2p²+3q-r²+2pr-5pqr

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

Step by step explanation:

1. Firstly write down the Equation as it is
2. Now, put Variable value into Equation which is given in the Question.
3. Last step is to make simplified the Equation by evaluating the each terms

=>2p²+3q-r²+2pr-5pqr

p= 3,q= 2 & r=5

Put variable's value into the Equation

=>2(3)²+3(2)-(5)²+2(3)(5)-5(3)(2)(5)

=>2×9+3×2-25+6×5-15×10

=>18+6-25+40-150

=>24-25-110

=> -1-110

=> -111

Hence,the value of 2p²+3q-r²+2pr-5pqr is -111

Extra information=>

• The above equation is a quadratic equation as the highest Power is 2.