Question

2) If p=a²b³ and q=a³b , find LCM(p ,q) and HCF(p ,q)​

Answer 1

Answer:

LCM=$a^{2} b^{3}$

HCF=$a^{2}b$

Step-by-step explanation:

For LCM,

As p and q have to reach a common number, the highest common number they have will be $a^{2} b^{3}$

For HCF,

They need to have something in common between them and $a^{2}b$ is that number.

Please do mark me if you feel I deserve it :)