Question

2. If p and q are the roots of the equation .x2 - px +q=0, then the value of p and a
(a) p = 1 and q = 0 (b) p = 0 and q=1 (c) p = -2 and q =0 (d) p = -2 and q = 1​

Answer 1

option a) and c)

We know sum of roots of quadratic equation is = - (coefficient of x)/(coefficient of x^2)

p+q = -(-p)/(1)

p+q = p

q = 0

as q = 0

equation get reduced to

x^2 - px + 0 = 0

x(x-p) =0 (factoring)

so x= 0 and x = p

this means that any real value of p would satisfy this conditions.

there q = 0 and p= 1

q = 0 and p =-2 are solutions.