Question

2. If Q is the point of intersection of the medians of
a triangle ABC, prove that QA +QB + QC =0.​

Answer 1

Step-by-step explanation:

may I help you............................

Answer 2

Step-by-step explanation:

SWER

Let

a

,

b

,

c

be the position vector of vertices

A,B.C respectively. then position vector of

centroid Q is

3

a

+

b

+

c

LHS =

QA

+

QB

+

QC

=(

QA

−

OQ

)+(

OB

−

OQ

)+(

OC

−

OQ

)

=

OA

+

OB

+

OC

−3

OQ

=

a

+

b

+

c

−3(

3

a

+

b

+

c

)

=

a

+

b

+

c

−

a

−

b

−

c

=

0