Math, asked by meghadawle86, 11 months ago

(2)
If
sin e + sin2 0 = 1,
show that :
cos2 e + cos4 0 = 1.​

Answers

Answered by sathwikshetty98
6

Answer:

 \sin(x)  \times  { \sin(x) }^{2}  = 1

 \sin(x)  = 1 -  { \sin(x) }^{2}

SINCE, 1-sin2x =cos2x

 \sin(x) =  { \cos(x) }^{2}

SQUARING ON BOTH SIDES

 { \sin(x) }^{2}  =  { \cos(x) }^{4}

Since,sin2x=1-cos2x

1 -  { \cos(x) }^{2}  =  { \cos(x) }^{4}

 { \cos(x) }^{2}  +  { \cos(x) }^{4}  = 1

HERE THETHA IS CONSIDERED X

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