2] If sina=0.8 Find cos3a
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Given:
Sin A = 0.8
Sin A = 8/10
Sin A = Perpendicular/ Hypotenuse. :Base=B, Perpendicular=P, Hypotenuse=H
P/H =8/10
P=8
H=10
H^2=Base^2+P^2 :Pythagoras Theorem
10^2=B^2+8^2
100=B^2+64
B=√(100-64)
B=√36
B=6
Cos A = Base/ Hypotenuse
Cos A = 6/10
Cos A = 3/5
Cos^3 A = (3/5)^3
Cos^3 A = 27/125.
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