Question

2. If tan-'3+ tan-'x = tan
8,then the value of x is equal to :
3.
(b)​

Answer 1

Answer:

Step-by-step explanation:

Use

$tan^{-1}(a)+tan^{-1}(b)=tan^{-1}(\frac{a+b}{1-ab} )$

So equation is nothing but

$(tan^{-1}\frac{3+x}{1-3x} )=tan^{-1}(8)$

Compare

$\:\:\:\:\:\:\:\:\frac{3+x}{1-3x}=8\\\\\implies 3+x=8-24x\\\\\implies 25x = 5\implies x={1 \over 5}$