Question

2) If tan e
3
then find the values of seco and cose
4​

Answer 1

Answer:

$\tan(e) = 3 \\ \frac{ p }{ b } = \frac{3}{1} \\ab (p) = 3 \\bc( b )= 1 \\ in \: rt \: angled \: triangle \: abc \\ ( ab)^{2} + (bc)^{2} = (ac)^{2} \\ 9 + 1 = {h}^{2} \\ h = \sqrt{10} \\ \\ \\ \\ \sec(e) = \frac{h}{b} \\ \: sece = \sqrt{10} \\ \\ cose = \frac{1}{ \sec(e) } \\ \sec(e) = \frac{1}{ \sqrt{10} }$