2. If tangents PA and PB from a point P to a circle with centre O are
inclined to each other at an angle of 70°, then Z POA is equal to
cent
March
(A) 70°
(B) 55°
(C) 100°
(D) 40°
Answers
Answered by
5
Answer:
(B) 55
answer
POA + PAO + APO =180
POA + 90 + 35 = 180
POA + 125 = 180
POA = 180 - 125
POA = 55
Attachments:
Answered by
1
Answer:
B
Explanation:
In triangle APO
angle A=90
angle P=35(half of 70)
angle O=?
A+P+O=180(The sum of triangle is 180)
90+35+O=180
O=55
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