Question

2. If the area of a rectangle is (6a3+5a2+5a+12) sq. units and its length is (3a+4) units, find the breadth

Answer 1

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Let length of rectangle = x units

And width of rectangle = y units

Area of rectangle = length * width = x*y

The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units.

So

Decrease the length by 5 unit so new length = x - 5

Increase the width by 3 unit so new width = y + 3

New area is reduced by 9 units

So new area  = xy – 9

Plug the value in formula length * width = area we get

(x  - 5)(y + 3) = xy  - 9

Xy  + 3x – 5y – 15  = xy – 9

Subtract xy both side we get

3x - 5y  = 6                 …(1)

If we increase the length by 3units and the breadth by 2 units, the area increases by 67 square units.

Increase the length by 3 unit so new length = x +3

Increase the width by 2 unit so new width = y + 2

New area is increased  by 67 units

So new area  = xy + 67

Plug the value in formula length * width = area we get

(x  +3)(y + 2) = xy  +  67

Xy  + 2x  +  3y  +  6  = xy + 67

Subtract xy both side we get

2x  +  3y = 61                         …(2)*3

3x - 5y  = 6                 …(1)*2

Cross multiply the coefficient of x we get

6x + 9 y = 183

6x -10y  =12

Subtract now we get

19 y = 171

Y = 171/19 = 9

Plug this value of y in equation first we get

2x + 3* 9 = 61

2x  = 61 – 27

2x = 34

X = 34/2 = 17

So length is 17 units and width is 9 units

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Answer 2

Answer:

l=>17 unit

b=>9unit

Step-by-step explanation:

Let length of rectangle = x units

And width of rectangle = y units

Area of rectangle = length * width = x*y

The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units.

So

Decrease the length by 5 unit so new length = x - 5

Increase the width by 3 unit so new width = y + 3

New area is reduced by 9 units

So new area = xy – 9

Plug the value in formula length * width = area we get

(x - 5)(y + 3) = xy - 9

Xy + 3x – 5y – 15 = xy – 9

Subtract xy both side we get

3x - 5y = 6 …(1)

If we increase the length by 3units and the breadth by 2 units, the area increases by 67 square units.

Increase the length by 3 unit so new length = x +3

Increase the width by 2 unit so new width = y + 2

New area is increased by 67 units

So new area = xy + 67

Plug the value in formula length * width = area we get

(x +3)(y + 2) = xy + 67

Xy + 2x + 3y + 6 = xy + 67

Subtract xy both side we get

2x + 3y = 61 …(2)*3

3x - 5y = 6 …(1)*2

Cross multiply the coefficient of x we get

6x + 9 y = 183

6x -10y =12

Subtract now we get

19 y = 171

Y = 171/19 = 9

Plug this value of y in equation first we get

2x + 3* 9 = 61

2x = 61 – 27

2x = 34

X = 34/2 = 17

So length is 17 units and width is 9 units

HOPE IT HELPS

note:- maine ye answer upar waale answer se chapa hai sry for that