Question

2.
If the average of squares of first n even numbers is
2(n+1)(2n+1)/m
then m^2 -2m-3=​

Answer 1

Answer:

EvenSum = 22 + 42 + 62 + .... + (2n)2

= 4 x (12 + 22 + 32 + .... + (n)2)

= 4n(n+1)(2n+1)/6

= 2n(n+1)(2n+1)/3

Answer 2

Answer:

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