Question

2. If the diagonals of a square are 10 cm each, find the
side of the square.​

Answer 1

Answer:

hello!

here's the answer!

Step-by-step explanation:

Let ABCD be the given square,

therefore, AB= BC= CD =DC = x

AC = DB = 10cm

But,

Angles of a square are 90°

therefore,

by Pythagoras theorem

in triangle ABC

AC² = AB² + BC²

10² = x +x

100 =2 x²

x ²= 50

x = 5√2

Answer 2

Answer:

5

Step-by-step explanation:

Formula= a^2 + b^2 =  hypotenuse

Lets assume the side as "a"

as the shape is a square

b^2=a^2

so,

a^2 + a^2 = 10^2

2a^2=10^2

square get cancelled

2a=10

a=10/2

Hence 1 Side = a = 5