Question

2) If the discriminant of a quadratic equation kx (x-2) + 6 = 0) is equal, then the value of k is
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Answer 1

Answer:

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Step-by-step explanation:

$k {x}^{2} - 2kx + 6 = 0 \\ d = {b}^{2} - 4ac = 0 \\ {( - 2k)}^{2} - 4 \times k \times 6 = 0 \\ 4 {k}^{2} - 24 k = 0 \\ 4 {k}^{2} = 24k \\ = > k = 6$

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Answer 2

kx ( x - 2) + 6 = 0

kx² - 2kx + 6 = 0

a = k, b = -2k, c = 6.

D = b² - 4ac

0 = ( -2k )² - 4 × k × 6    { D = 0 ( given ) if roots of a quadratic eqⁿ are equal then D = 0 }

0 = 4k² - 24k

0 = 4k ( k - 6 )

k - 6 = 0

k = 6