Question

2. If the error in the measurement of
radius is 2%, then the error in the
determination of volume of the sphere will be
a) 8%
b) 2%
c) 4%
A) 69​

Answer 1

Answer:

Percentage error in radius is given as 2% i.e.    

r

Δr

​  

×100=2 %

Volume of sphere   V=  

3

4π

​  

r  

3

 

Percentage error in volume    

V

ΔV

​  

×100=3×  

r

Δr

​  

×100=3×2=6 %

Explanation: