Question

(2)
If the frequency of revolution of an object changes
from 2 Hz to 4 Hz in 2 seconds, calculate its
angular acceleration.​

Answer 1

Answer:

One revolution is equal to 2π radians, hence[1][2]

{\displaystyle \omega ={{2\pi } \over T}={2\pi f},}\omega ={{2\pi } \over T}={2\pi f},

where:

ω is the angular frequency or angular speed (measured in radians per second),

T is the period (measured in seconds),

f is the ordinary frequency (measured in hertz) (sometimes symbolised with ν)