Question

2. If the H.C.E of 408 and 1032 is expressible in the form of 1032 x 2 - 408 x y, then find the value of y​

Answer 1

Answer:

By Euclid's division algorithm

1032=408×2+216

408=216×1+192

216=192×1+24

192=24×8+0

Since the reminder becomes 0 here, so HCF of 408 and 1032 is 24 now

1032m−408×5=HCF of there number

1032m−408×5=24

1032m=2064

m=2