Math, asked by mummy55070, 2 months ago


2. If the length
, breadth and height of a cuboid are in the ratio 6 : 5: 4 and the total surface area of
the cuboid is 33300 cm2, then the breadth of the cuboid is
(a) 85 cm
(b) 75 cm
(d) cannot be determined
(c) 65 cm

Answers

Answered by MoodyCloud
115

Answer:

Option (b) is correct. Breadth of cuboid is 75 cm.

Step-by-step explanation:

Given that,

Length, breadth and height of cuboid are in ratio 6:5:4.

Total surface area of cuboid is 33300 cm².

Let,

Length, breadth and height of cuboid be 6x, 5x and 4x.

We know,

Total surface area of cuboid = 2(lb + bh + lh)

[l is length, b is breadth and h is height of cuboid]

Put values :

 \longrightarrow 33300 = 2×[(6x × 5x)+(5x × 4x)+(6x × 4x)]

 \longrightarrow 33300 = 2 × (30x² + 20x² + 24x²)

 \longrightarrow 33300 = 60x² + 40x² + 48x²

 \longrightarrow 33300 = 148x²

 \longrightarrow 33300/148 = x²

 \longrightarrow 225 = x²

 \longrightarrow x =√225

 \longrightarrow \pmb{\sf x = 15}

So,

Length = 6x = 6×15 = 90

Breadth = 5x = 5×15 = 75

Height = 4x = 4×15 = 60

Therefore,

Breadth of cuboid is 75 cm.

Answered by BrainlyRish
47

Given : The length, breadth and height of a cuboid are in the ratio 6 : 5: 4 & Total surface area of the cuboid is 33300 cm²

Need To Find : Breadth of Cuboid .

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

❍ Let's Consider the Length, Breadth & Height of Cuboid be 6x , 5x & 4x respectively.

\dag\frak{\underline { As,\:We\:know\:that\::}}\\\\

\star\boxed {\pink{ \small {\sf{ Total \:Surface \:Area\:_{(Cuboid)} = 2 ( lb + bh + lh ) }}}}\\\\

Where,

  • l is the Length of Cuboid, b is the Breadth of Cuboid & h is the Height of Cuboid.

\underline {\frak{\star\:Now \: By \: Substituting \: the \: known\: Values \::}}\\

\qquad:\implies \sf{ 33300 = 2 \bigg( ( 6x \times 5x ) + (5x \times 4x ) + ( 6x \times 4x )\bigg) }\\\\

\qquad:\implies \sf{ 33300 = 2 \bigg(  30x^{2}  +  20x^{2} + 24x^{2} \bigg) }\\\\

\qquad:\implies \sf{ 33300 =   60x^{2}  +  40x^{2} + 48x^{2}  }\\\\

\qquad:\implies \sf{ 33300 =  148x^{2}  }\\\\

\qquad:\implies \sf{ \cancel {\dfrac{33300}{148}} =  x^{2}  }\\\\

\qquad:\implies \sf{ 225 =  x ^{2} }\\\\

\qquad:\implies \sf{ \sqrt{225} =  x^{2}  }\\\\

⠀⠀⠀⠀⠀\underline {\boxed{\pink{ \mathrm { x = 15\: cm}}}}\:\bf{\bigstar}\\

Therefore,

  • Length of Cuboid is 6x = 6 × 15 = 90 cm .

  • Breadth of Cuboid is 5x = 5 × 15 = 75 cm

  • Height of Cuboid is 4x = 4 × 15 = 60 cm .

⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀\therefore {\underline{ \mathrm { Hence , \:  Breadth \:of\:Cuboid \:is\:\bf{75\: cm}}}}\\

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

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